Differentiate $e^{\frac{y^3}{x^9}}$ with respect to $x,$ assuming that $y$ is implicitly a function of $x.($Use symbolic notation and fractions where needed. Use $y^{\text{'}}$ in place of $\frac{dy}{dx}.)$

$\frac{d}{dx}(e^{\frac{v^{\text{'}}}{x^0}})=$