Draw a schematic that demonstrates this truth table

\begin{tabular}{|c|c|c|c|} \hlinea & b & c & s \\ \hline 0 & 0 & 0 & 0 \\ \hline 0 & 1 & 0 & 1 \\ \hline 1 & 0 & 0 & 1 \\ \hline 1 & 1 & 1 & 0 \\ \hline \end{tabular}