During a lecture demonstration of single-slit diffraction, a laser beam that has a wavelength = 550 [nm] passes through a vertical slit of gap a = 0.2 [mm] and hits a screen. All angles are in degrees. A diffraction pattern is observed on the screen, as shown in the below figure. 1x550x10 0.2x10- Osin () L a) [2 points] Considering = 550 [nm] and a = 0.2 [mm], the angle corresponding to the first dark fringe (0) will be given by: Osin((1/2)x550x10 Screen- W= W 0.2x10- Osin((1/2x02x10- 550x10 b) [3 points] Considering = 550 [nm] and a = 0.2 [mm], calculate the angle corresponding to the first dark fringe (0) 0 = c) [5 Points] If the angle corresponding to the first dark fringe is found to be 0 = 0.26*, and the screen is located at a distance L = 8 [m] from the slit. Calculate y. the location of the first dark fringe. y = [m] d) [5 Points] If the location of the first dark fringe is found to be y = 0.14 [m]. Find w, the width of the central bright fringe. [m]