Question: During a very quick stop, a car decelerates at 6 . 6 m s 2 . Assume the forward motion of the car corresponds to

During a very quick stop, a car decelerates at 6.6ms2. Assume the forward motion of the car corresponds to a positive direction for the rotation of the tires (and that they do not slip on the pavement).
Randomized Variables
at=6.6ms2
r=0.25m
0=96rads
Part (a)
What is the angular acceleration of its tires in rads2, assuming they have a radius of 0.25 m and do not slip on the pavement?
Part (b)
How many revolutions do the tires make before coming to rest, given their initial angular velocity is 96rads?
Part (c)
How long does the car take to stop completely in seconds?
Part (d)
What distance does the car travel in this time in meters?
Part (e)
What was the car's initial speed in ms?
During a very quick stop, a car decelerates at 6

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