Edit my MIPS/Assembly factorial code.

Hello, I'm asked to write a program that asks user for integer n, between 0 to 20. The program should find n!. I think I put my error message in the wrong place but i want it to loop to enter another number if the first number gives an error. Please try to use as much as possible as my original code, feel free to add stuff but it should not be too advance as we are just now learning how to use assembly

An Example of sample input and output would be:

Enter an integer value between 0-10? 11 ==> **** ERROR: 11 is not within the range. Enter another number.

Enter an integer value between 0-10? -3 ==> **** ERROR: -3 is not within the range. Enter another number.

Enter an integer value between 0-10? 0 0! =1

Enter an integer value between 0-10? 4 4! =24

.data

enter: .asciiz "Please enter an integer value between 0-20" error: .asciiz "Error, the number is not within the range. Enter another number"

.text

li $v0,4 la $a0, enter syscall

li $v0, 5 syscall add $s0, $v0, $0

li $t2, 1 li $t3, 20

fact: li $t0, 1 move $t1, $a0

loop: blez $t1, done blt $t1, $t2, errormessage bgt $t1, $t3, errormessage mul $t0, $t0, $t1 addi $t1, $t1, -1 j loop

done: move $v0, $t0

li $v0, 10 syscall

errormessage: li $v0,4 la $a0, error syscall j loop