Equation (2.16) gives 2 01.02 = 2 12y + 2 = [(63.65 N)d+2253.5 Nm] (2674 Nm)2 + [(63.65 N)d+2253.5 Nm] d3 It can be shown that unless d is in the thousands of meters, that one of these stresses will be positive, and the other negative. Therefore, for MSST, Eq. (6.6) is: 01-03 S.. 350 MPa 2 = 175 MPa Substituting for the stresses and solving yields d = 0.0341 m. Therefore, a 35 mm diameter cross-section is a good design designation. For DET, Equations (6.9) and (6.11) give: 1 1 (01-02) + (01-03) + (02-03 ) 2 1/2 == 2 (01) + ( - 03) + (3)2 1/2 = 175 MPa This is solved numerically as d = 0.0287 m. Therefore, a 35 mm diameter cross section is still accept- able.