a) Given the unsteady state flow of oil in a well near two orthogonal no flow...

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a) Given the unsteady state flow of oil in a well near two orthogonal no flow boundaries as shown below, explain how you would use the superposition principle to calculate pressure at any given point in the reservoir at any given time. Please explain the purpose of each superposition well. d Producing Wll No Flow Boundary. d b) Write the equation to calculate the pressure at a given time at point X shown below. Producing Well No Flow Boundary R d c) Given the oil production rate of 200 bbl/d, oil formation volume factor of 1 rbbl/stb, oil viscosity of 0.5 cp, permeability of 50 md, total compressibility of 15 x 10 * psi 1, porosity of 10% and the distance from the well to no flow boundary (d) of 7000 ft, find the pressure drop at the point marked by X in the figure below 1 day after the well starts producing. d. Producing Well No Flow Boundary d/2 Error Function 10 EXPONENTIAL INTEGRAL VALUES Eil-x) =- du For x<0.02 Ei(-x) - Intx)•0.577 3. -,02 -04 -.06 -.08 -10 1.0 Eil-x) 0.8 0.6 0.4 * 0.3 0.2 0.1 08 06 .04 03 02 1.5 -2.0 Ei(-x) -0.5 -1.0 -2.5 -3.0 Fig. 7.11. 2. a) Given the unsteady state flow of oil in a well near two orthogonal no flow boundaries as shown below, explain how you would use the superposition principle to calculate pressure at any given point in the reservoir at any given time. Please explain the purpose of each superposition well. d Producing Wll No Flow Boundary. d b) Write the equation to calculate the pressure at a given time at point X shown below. Producing Well No Flow Boundary R d c) Given the oil production rate of 200 bbl/d, oil formation volume factor of 1 rbbl/stb, oil viscosity of 0.5 cp, permeability of 50 md, total compressibility of 15 x 10 * psi 1, porosity of 10% and the distance from the well to no flow boundary (d) of 7000 ft, find the pressure drop at the point marked by X in the figure below 1 day after the well starts producing. d. Producing Well No Flow Boundary d/2 Error Function 10 EXPONENTIAL INTEGRAL VALUES Eil-x) =- du For x<0.02 Ei(-x) - Intx)•0.577 3. -,02 -04 -.06 -.08 -10 1.0 Eil-x) 0.8 0.6 0.4 * 0.3 0.2 0.1 08 06 .04 03 02 1.5 -2.0 Ei(-x) -0.5 -1.0 -2.5 -3.0 Fig. 7.11. 2.