Evaluate ${\displaystyle \underset{\frac{1}{2}}{\overset{1}{}}}(2x-1{)}^{2019}dx$

$($A$)\frac{1}{4040}$

$($B$)\frac{2^{2020}}{4040}$

$($C$)2^{2019}-1$

$($D$)\frac{2^{2020}-1}{4038}$

$($E$)$ None of these is correct