Question: evaluate This is an application of complex integration in real integration. *2* de 1+ a - 2a cos 0' where a is a real
evaluate This is an application of complex integration in real integration. *2* de 1+ a - 2a cos 0' where a is a real constant: (a) using the fact that a < 1. (b) using the fact that a > 1. (c) [bonus 5 marks] What about |a| = 1?
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
