Consider the reaction: 2Mg + O2 2MgO HRxn = -1204 kJ/mol. Suppose you react 2.43 g

Consider the reaction: 2Mg + O2 → 2MgO ΔHRxn = -1204 kJ/mol. Suppose you react 2.43 g of Mg powder with 1.6 g of O2 in a calorimeter. It contains 500 ml of water and is equilibrated to a starting temperature of 25°C. Calculate the temperature the thermometer will read after the reaction occurs. The specific heat of water is c = 4.18 J/g°C. Watch your signs.

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mole of mg mole of o 243 24305 00999 mole 2 1... View the full answer