Question: F y B = Concentrated force acting on the joint as shown in the figure ( Magnitude is 2 8 1 bf ) The links

FyB= Concentrated force acting on the joint as shown in the figure (Magnitude is 281bf)
The links AB and BC have a square cross-section of 40mm40mm
Simplifying assumptions you are allowed to consider:
The pin joints at A,B and C are frictionless
The slider at C can slide horizontally without any frictional resistance from
support at the bottom
The slider does not restrict rotation along z-axis of link BC about point C
The slider stays horizontal as shown in the picture
Wall support shown in grey are rigid
Do the following:
Draw a combined Free Body Diagram of the entire structure (include links, slider and spring)
For the links AB and BC, obtain reaction forces and moments at A,B, and C
Compute FxA,FyA,FzA,MxA,MyA,MzA
Compute FxB,FyB,FzB,MxB,MyB,MzB
Compute FxC,FyC,FzC,MxC,MyC,MzC
Find the location where bending moment is highest
Find the location where the stresses are highest
Find factor of safety at that point assuming yield strength to be 1500 MPa
Draw a 3D stress element (cube) showing the state of stress that point
Compute absolute maximum shear stress
Assuming Tresca or maximum shear stress as the failure criteria, compute the
safety factor
If the linear spring has the spring rate of 10kNm, compute the net deformation of that spring
NOTE: All locations must be identified in coordinates by assuming origin of the coordinate system
at a suitable location. Unstretched length of spring is 100 mm .
F y B = Concentrated force acting on the joint as

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