Question: Fig. 6.16 Left: Sketch for X = 0 X= L the tube and membrane Tube and membrane diffusion conc 0 conc n cross-sectional area A

 Fig. 6.16 Left: Sketch for X = 0 X= L thetube and membrane "Tube and membrane diffusion" conc 0 conc n cross-sectional

Fig. 6.16 Left: Sketch for X = 0 X= L the tube and membrane "Tube and membrane diffusion" conc 0 conc n cross-sectional area A location of membrane of conductance GM for 0 W? (Hint: Your answer to this part should be very simple.) (h) Compare P2 to Q; in the "Gambler's ruin" example in Chap. 5. Random Walks: Brownian Motion and the Tree of Life.Problem 5: Calculating Probabilities Using Solutions to the Steady-State Diffusion Equation: Repressor and Operators A certain DNA binding proteinthe repressor (R)binds to a linear segment of yeast DNA and then undergoes onedimensional diffusion along the DNA. However, there are two particular sequences of bases on the DNAoperator l (01) and operator 2 (02)to which R binds very tightly. If R reaches either 01 or 02, binding is so tight that R may be considered to be captured by 01 or 02. Your goal in this problem is to determine the probability that R is eventually captured at Ol (call it P1) and the probability that R is eventually captured at 02 (call it P2). These two alternatives are the only two possibilities. and they are mutually exclusive. 0] is located at .x = 0. R initially binds to the DNA at x = W. 02 is located at x = L. We have 0

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