Figure 2: 120.3 cm 64.8 cm 92.5 cm 37.0 cm Mirror Question 4 (5 points) Please...

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Figure 2: 120.3 cm 64.8 cm 92.5 cm 37.0 cm Mirror Question 4 (5 points) Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 62.3 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.17 cm, located a distance y 48.1 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of Glass (n=1.5) 45.5 cm 65.0 cm 26.0 cm 91.0 cm Air (n=1) Question 5 (5 points) Please refer again to Figure 2. This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 52.4 degrees, y = 49.0 cm and h = 1.70 cm. What is x now? Figure 2: 120.3 cm 64.8 cm 92.5 cm 37.0 cm Mirror Question 4 (5 points) Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 62.3 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.17 cm, located a distance y 48.1 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of Glass (n=1.5) 45.5 cm 65.0 cm 26.0 cm 91.0 cm Air (n=1) Question 5 (5 points) Please refer again to Figure 2. This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 52.4 degrees, y = 49.0 cm and h = 1.70 cm. What is x now? Figure 2: 120.3 cm 64.8 cm 92.5 cm 37.0 cm Mirror Question 4 (5 points) Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 62.3 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.17 cm, located a distance y 48.1 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of Glass (n=1.5) 45.5 cm 65.0 cm 26.0 cm 91.0 cm Air (n=1) Question 5 (5 points) Please refer again to Figure 2. This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 52.4 degrees, y = 49.0 cm and h = 1.70 cm. What is x now? Figure 2: 120.3 cm 64.8 cm 92.5 cm 37.0 cm Mirror Question 4 (5 points) Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 62.3 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.17 cm, located a distance y 48.1 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of Glass (n=1.5) 45.5 cm 65.0 cm 26.0 cm 91.0 cm Air (n=1) Question 5 (5 points) Please refer again to Figure 2. This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 52.4 degrees, y = 49.0 cm and h = 1.70 cm. What is x now?

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Solutions to questions 4 and 5 Question 4 Given Angle of incidence of light beam on mirror 623 Distance between mirror and glass paney 481 cm Thickness of glass paneh 117 cm To find Horizontal distanc... View the full answer