Find the following for the hyperbola y-16x-128x-4y-268-0 y-4y-16 (x+8x) = 268 Convert y-4y-16(x+8x) = 268 into...

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Find the following for the hyperbola y²-16x²-128x-4y-268-0 y²-4y-16 (x²+8x) = 268 Convert y²-4y-16(x²+8x) = 268 into standard form Write y²-4y-16 (x² +8x) =2 The center of the hyperbola is at The transverse axis is parallel to the =268 in standard form: The stan (y-k)² (x-h)² b² a The value of a = - the value of b=and the focal length c = (Simplify your answer. Type an exact answer, using radicals as needed.) ALL = 1 using the complete the square process covered in class. A Find the following for the hyperbola y²-16x²-128x-4y-268-0 y²-4y-16 (x²+8x) = 268 Convert y²-4y-16(x²+8x) = 268 into standard form Write y²-4y-16 (x² +8x) =2 The center of the hyperbola is at The transverse axis is parallel to the =268 in standard form: The stan (y-k)² (x-h)² b² a The value of a = - the value of b=and the focal length c = (Simplify your answer. Type an exact answer, using radicals as needed.) ALL = 1 using the complete the square process covered in class. A

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The given equation of hyperbola is y 16x 128x 4y 268 0 Converting this equation into standard ... View the full answer