Find the function y1 of t which is the solution of 36y" - 25y = 0 with initial conditions y1(0) = 1, y', (0) = 0. y1 = Find the function y2 of t which is the solution of 36y" - 25y = 0 with initial conditions y2(0) = 0, y2(0) = 1. y2 = Find the Wronskian W (t) = W(y1, yz). ( Hint : write y1 and y2 in terms of hyperbolic sine and cosine and use properties of the hyperbolic functions). W (t ) = Remark: You should find that W is not zero and so y1 and y2 form a fundamental set of solutions of 36y" - 25y = 0