Please need an answer asap

Find the function y1 of t which is the solution of 49y' - 64y = 0 with initial conditions y1 (0) = 1, y, (0) = 0. 31 = 1 Find the function yz of t which is the solution of 49y' -64y = 0 with initial conditions y2 (0) = 0, 3/2(0) - 1. y2 = Find the Wronskian W (t) = W(y1, 32). ( Hint : write y1 and y2 in terms of hyperbolic sine and cosine and use properties of the hyperbolic functions). W (t) = Remark: You should find that W is not zero and so yj and y2 form a fundamental set of solutions of 49y" - 64y = 0. Note: You can earn partial credit on this problem. It can be shown that y1 = e 2 and y2 = xe 2 are solutions to the differential equation da2 + 4- dy + 4y = 0 on (-00, 00). dx (a) What does the Wronskian of y1, y2 equal on (-oo, co)? W ( y1, y2 ) = on (-00, 00 ). (b) Is {y1, y2} a fundamental set for the given differential equation? Choose v