Question: Find the general solution of the second order equationy''+4y'+4y = (t+1)*e^(-2t). The homogeneous differential equation t^2y'' + ty'-y = 0 has general solution y(t) =
Find the general solution of the second order equationy''+4y'+4y = (t+1)*e^(-2t).
The homogeneous differential equation t^2y'' + ty'-y = 0 has general solution y(t) = At + B/t, where A and B are arbitrary constants. Find a particular solution of the non-homogenous equation t^2y'' + ty'-y = t.
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Lets work through both parts of the given question stepbystep Part 1 Find the general solution of the second order equation y 4y 4y t1e2t Step 1 Solve ... View full answer

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