Find the indefinite integral by making the substitution $x=5tan().$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{{}^3}{\sqrt[\phantom{2}]{25+x^2}}dx$

$\frac{2\sqrt[\phantom{2}]{25+x^2}(x^3-25)}{3}+C$

$\frac{\sqrt[\phantom{2}]{25+x^2}(x^2-25)}{3}+C$

$\frac{\sqrt[\phantom{2}]{25+x^2}(x^2-50)}{3}+C$

$\frac{2\sqrt[\phantom{2}]{25+x^2}(x^2-50)}{3}+C$

$\frac{\sqrt[\phantom{2}]{25+x^2}(50-x^2)}{3}+C$