Find the integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}[\frac{-3}{\sqrt[3]{x}}-4\sqrt[\phantom{2}]{x}]dx$

A$.x^{\frac{2}{3}}-2x^{\frac{3}{2}}C$

B$.-3ln|x^{\frac{1}{3}}|-2x^{\frac{3}{2}}c$

c$.-\frac{9}{2}{x}^{\frac{2}{3}}-\frac{8}{3}{x}^{\frac{3}{2}}c$

D$.-2x^{\frac{2}{3}}-6x^{\frac{3}{2}}C$