Question: First, vitamin C (C 6 H 8 O 6 ) reacts with molecular iodine (I 2 , dark brown color) to produce the iodide ion

First, vitamin C (C6H8O6) reacts with molecular iodine (I2, dark brown color) to produce the iodide ion (I, colorless):

C6H8O6 (aq) + I2 (aq) → 2 H+ (aq) + 2 I (aq) + C6H6O6 (aq)           (Reaction 1)

When hydrogen peroxide is added, the iodide ion is oxidized back to molecular iodine:

2 I (aq) + 2 H+ (aq) + H2O2 (aq) → I2 (aq) + 2 H2O (l)           (Reaction 2)

Use the dilution equation (M1V1 = M2V2)  to calculate the concentrations of each reagent in the reaction mixture immediately after the solutions in Beaker 1 and Beaker 2 are mixed (the total volume is 30 mL for all experiments). These are the “initial concentrations” for the reaction, [C6H8O6]0 , [I]0 , and [H2O2]0

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