Question: FJ 1 2 2 . 4 Cu ( k ) + O 2 ( g ) = 2 Cu 2 0 CpCu ( k )

FJ12
2.4Cu(k)+ O2(g)=2Cu20 CpCu(k)=22+6 x10-3 TJ/molk (2980-1356K) Cp (k)=62+23x10-3 TJ/molK (2980-1200K) Cp (g)=30+4x10-3(J/molK)(2980-3000K): a)298 K AH AS b)600K AH AS AG

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