Question: For the 4-phase intersection, the following are given: The peak hour factor = 0.92, the approach speed is 50km/hr, the average vehicle length is 6m,

For the 4-phase intersection, the following are given: The peak hour factor = 0.92, the approach speed is 50km/hr, the average vehicle length is 6m, the intersection is leveled, and no all red time is applied on the intersection. Phase Width of approach Approach Lost Lane group Saturation flow (velh) peak hour volume (ver) time (sec) 1 850 121 2 West Approach 23 m (6 lanes in both i theo cch of width of 3.6 and a median of 2400 483 1.4 m) 2500 397 2600 584 East Approach 23 m B 2200 308 850 101 13.6 m 1 1500 260 3 South Approach (4 lanes for both directions eh of width of 3.0 m anda median of 1.6 m) 2 1200 210 1 1500 242 13.6 m (4 lanes for both North directions cach Approach of width of 3.0 manda median of 1.6 m) D 3 2 1200 200 Required sketch the intersection, (use a ruler and make your sketch representative or you can always use the AUTOCAD to draw). On the sketch you must locate all lane groups, the DHV for each lane group, and the dimensions Calculate the yellow time (to the nearest 0,5 sec) for the East - West Approaches and for the North - South Approaches . Use reaction time of 1 sec. and the value of a is 3.4 m/sec. (1 km/hr -0.278 m/sec.). Calculate the actual green time for all phases following the Webster method
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