For the equivalent force$-$couple system shown, the internal forces: $P=520N,T=250$ N$.$m$,$ and $M_x=70N.m$ are in the same directions shown in the figure. Knowing that the diameter is $40$ mm $,$ determine the following:

At point $"$H$"$

${}_y=,$MPa

$$

One possible correct answer is: $11\mathrm{.}14$

${}_{yx}=,$MPa

$$

One possible correct answer is: $19\mathrm{.}89$

${}_{yz}=,$MPa

$q,$

$q,$

At point $"$K$"$

${}_y=,$MPa

$$

One possible correct answer is: $0$

${}_{yx}=,$MPa

$$

One possible correct answer is: $0$

${}_{yz}=,$MPa

$q,$

$q,$

$$

One possible correct answer is: $20\mathrm{.}45$