Question: For the gas-phase reaction (A+2B-> C + D), the rate law is given as follows. -r(A) = k(A)C(A)C(B) The reaction rate constant (ka) is 1.00

For the gas-phase reaction (A+2B-> C + D), the rate law is given as follows. -r(A) = k(A)C(A)C(B) The reaction rate constant (ka) is 1.00 x10^-2 dm^3/(mol*s) at 150C. This reaction rate constant doubles when the reaction temperature is increased to 200C. Only equimolar mixture of A and B is fed to the continuous-stirred tank reactor (CSTR) at at 2 atm.

1-1) What is the activation energy for this reaction?

Ans) Ea = (kJ/mol)

1-2)what is the initial rate of reaction (X(A) = 0) at 100celcius?

Ans) -r(A) (mol/(m^3*h)) =

1-3) What would be the corresponding CSTR volume at 100C to achieve 90% conversion of the limiting reactant for a total molar feed rate of 2 mol/min.

Ans) V(CSTR) = (dm^3)

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