For the given position vectors $r(t)$ compute the unit tangent vector $T(t)$ for the given value $oft.$

$Ar(t)=($:$cos3t,sin3t$:$).$

Then $T(\frac{}{4})$

$Br(t)=($:$t^2,t^3$:$).$

Then $,$

$Cr(t)=e^{3t}i+e^{-5t}j+tk.$

Then $T(3)=$