Question: For the reaction: CHCl3 (g) + H2 (g) --> CH2Cl2 (g) + HCl (g). The rate law for this reaction was determined to be Rate

For the reaction: CHCl3 (g) + H2 (g) --> CH2Cl2 (g) + HCl (g). The rate law for this reaction was determined to be Rate = k [CHCl3] [H2]

a. The reaction is __________ order in CHCl3

b. The reaction is __________ order with respect to H2

c. The reaction is __________ order overall

d. Quadrupling the concentration of H2 while keeping the concentration of CHCl3 constant increases the reaction rate by __________ times

e. Doubling the concentration of CHCl3 while keeping the concentration of H2 constant increases the reaction rate by __________ times

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