force system using the equations of equilibrium.

Four forces act on a particle that is in equilibrium as

shown in $($Figure $1),$ where $F_3$ and $P$ are in the $xz-$

plane. The magnitude of one force is known to be $P$

$=800N.$

So the equilibrium of the point can be written as the following set of equations.

${\displaystyle \underset{?}{\overset{?}{}}}{F}_x=0,F_{1}cos(60)cos(30)-\frac{2}{3}{F}_2-F_{3}cos(30)+$Psin$(20),=0$

${\displaystyle \underset{?}{\overset{?}{}}}{F}_y=0,-F_{1}cos(60)sin(30)+\frac{2}{3}{F}_2,=0$

${\displaystyle \underset{?}{\overset{?}{}}}{F}_z=0,F_{1}sin(60)+\frac{1}{3}{F}_2+F_{3}sin(30)-$Pcos$(20),=0$

Solve the system of equations for each of the unknown forces. What is the magnitude of $F_1?$

Express your answer to three significant figures with appropriate units.

Incorrect; Try Again; One attempt remaining

Part E

What is the magnitude of $F_2?$

Express your answer to three significant figures with appropriate units.

$F_2=$