Formally $lim\mathrm{????}\to \mathrm{????}\mathrm{????}(\mathrm{????})=\mathrm{????}$ means that given any $\mathrm{????}\mathrm{????}\mathrm{????}\mathrm{????}>0,$ there exists $\mathrm{????}>0$ such that for all $\mathrm{????}\ne \mathrm{????},$ if $|\mathrm{????}-\mathrm{????}|<\mathrm{????},$ then $|\mathrm{????}(\mathrm{????})-\mathrm{????}|<\mathrm{????}\mathrm{????}\mathrm{????}\mathrm{????}.$When demonstrating that $lim\mathrm{????}\to 5\mathrm{????}2-10\mathrm{????}=-25$ with $\mathrm{????}\mathrm{????}\mathrm{????}\mathrm{????}=0\mathrm{.}7,$ find the largest number $\mathrm{????}$ such thatif $,0<|\mathrm{????}-5|<\mathrm{????},$ then $,|\mathrm{????}2-10\mathrm{????}+25|<0\mathrm{.}7.$$\mathrm{????}=$

 

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Formally lime f(x) = L means that given any > 0, there exists > 0 such that for all xc, if |xc| <8, then |f(x) - L| < E. When demonstrating that lim, 5 x - 10x = -25 with = 0.7, find the largest number & such that if 0 Formally lime f(x) = L means that given any > 0, there exists > 0 such that for all xc, if |xc| <8, then |f(x) - L| < E. When demonstrating that lim, 5 x - 10x = -25 with = 0.7, find the largest number & such that if 0

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To demonstrate that limx to 5 2x2 10 25 with 07 we need to find the larg... View the full answer