Given:

$(1)2H2(g)+02(g)2H2O(l)H=-571\mathrm{.}6kJ$

$(2)N2O5(g)+H2O(l)2$HNO$3(l)H=-73\mathrm{.}7kJ$

$(3)\frac{1}{2}N2(g)+\frac{3}{2}O2(g)+\frac{1}{2}H2(g)$HNO$3(l)H=$

$-174\mathrm{.}1kJ$

Calculate the in $kJ)$ for $N2(g)+\frac{5}{2}O2(g)N2O5(g)$

fill in blank

Write answer in decimal form to three significant figures.

Not in scientific notation.

No units in answer.

Make sure to include the correct sign.