Given a highway circular curve with an intersection angle $12\mathrm{.}5,$ radius of curve of $580$ feet,

and a PI station $9+25\mathrm{.}5,$ the station PT is most nearly:

$9+50$

$10+00$

$10+50$

$11+00$

Given a highway circular curve with an intersection angle $12\mathrm{.}5,$ radius of curve of $580$ feet,

and a PI station $9+25\mathrm{.}5,$ the station PT is most nearly:

$9+50$

$10+00$

$10+50$

$11+00$