Given that A) f(x) = 65x 4 − 72x 3 − 1.5x 2 + 16.5x − 1, the initial guess for Newton’s method is x0 = 0.1, the interval for bisection method is [0, 1]. B) f(x) = x 4 − 6x 2 + 12x − 8, the initial guess for Newton’s method is x0 = 1.5, the interval for bisection method is [1, 3]. Sketch the graph of the function y = f(x) and the y-axis onto the same figure. Comment on the point of intersection. Compare the bisection method and Newton’s method to find the real number x satisfying f(x) = 0, where