Question: Given that y 1 = e 6 x is a solution of the DE y 1 3 y + 4 2 y = 0 .

Given thaty1=e6xis a solution of the DEy13y+42y=0. Using the reduction of order method a second solution of the equation isy2=uy1where u is
e2x
e7x
e1x
x

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