Question: Given the balanced equation: 4 Cu + O2 --> 2 Cu20 Molar masses (g/mol): Cu = 63.55; O2 = 32.00; Cu20 = 143.09 A)

Given the balanced equation: 4 Cu + O2 --> 2 Cu20 Molar masses (g/mol): Cu = 63.55; O2 = 32.00; Cu20 = 143.09 A) How many grams of Cu2O can be produced when 28 g of Cu is used in a reaction? B) Determine the limiting reactant for Cu2O production when 30.2 g of Cu is combined with 39.9 g O2 in a reaction. Your answer should be in the form "The limiting reactant is C) If the actual yield of Cu20 from the reaction in part B is 14.38 g, what is the percent yield?

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