Given the bar displacement problem shown in the diagram below. The bar has uniform area 0.0005m2 and has material with modulus of elasticity E=1.0GPa. The bar is meshed using unequal sized elements of length L=1.0m and L=0.25m, as shown in the diagram. The mesh nodes are listed in numerical order from left to right. The basis functions for element 1 are given as: N1(x)=1x and N2(x)=x The loading along the bar is given by the function: l(x)=(4+4x)kN/m X=0mX=1.25m Use this to form RHS force vector for the local system for element 1 , LAE[1111]{u1u2}={f1f2}={abN1l(x)dxabN2l(x)dx} by answering the following: a) state the lower bound (a) when performing the integral for element 1. Unanswered b) state the upper bound (b) when performing the integral for element 1. Unanswered calculate and insert the integral contribution for f1 in the above RHS vector. Insert answer in N (NOT kN) to 3 decimal places. Unanswe 1) calculate and insert the integral contribution for f2 in the above RHS vector. Insert answer in N (NOT kN) to 3 decimal places. given the second element's stiffness equaions, LAE[1111]{u2u3}={1041.66666666671083.3333333333} form the integral component of global force vector using your previous solution. State in N (NOT kN) to 3 decimal places