Given the following data: H2 (g) + 1/2 O2 (g)-----> H2O (l) delta H=-285.8 KJ N2O5 (g)+
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Question:
Given the following data:
H2 (g) + 1/2 O2 (g)-----> H2O (l) delta H=-285.8 KJ
H2 (g) + 1/2 O2 (g)-----> H2O (l) delta H=-285.8 KJ
N2O5 (g)+ H2O (l)------->2HNO3 (l) delta H=-76.6 KJ
1/2 N2 (g) + 3/2 O2 (g) + 1/2 H2 (g)----->HNO3 (l) delta H=-174.1 KJ
1/2 N2 (g) + 3/2 O2 (g) + 1/2 H2 (g)----->HNO3 (l) delta H=-174.1 KJ
Calculate Delta H for the reaction:
2N2 (g) + 5 O2 (g)-----> 2 N2O5 (g)
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