Question: Given the following reactions: Anode: NO3-+ 2H+ + P- --> NO2 + H20 Cathode: 2H+ + 2e- --> H2 Redox: 2N02(e) + 2 H20 (1)

Given the following reactions:

Anode: NO3-+ 2H+ + P- --> NO2 + H20

Cathode: 2H+ + 2e- --> H2

Redox: 2N02(e) + 2 H20 (1) -=> 2NO3-(an) + 2H+(ag) + H2(g)

Conditions: 0.15 atm] [0.18 atm] [0.1 M] [0.67 atm]

Find the pH. if E = - 0.70 V.

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