Question: Given this linear programming model, solve the model and then answer the questions that follow. Maximize 12 x 1 + 18 x 2 + 15
Given this linear programming model, solve the model and then answer the questions that follow.
| Maximize | 12x1 + 18x2+ 15x3 | where x1 = the quantity of product 1 to make etc. |
| Subject to |
| Machine | 5x1 | + | 4x2 | + | 3x3 | 160 | minutes | |
| Labor | 4x1 | + | 10x2 | + | 4x3 | 288 | hours | |
| Materials | 2x1 | + | 2x2 | + | 4x3 | 200 | pounds | |
| Product 2 | x2 | 16 | units | |||||
| x1, x2, x3 | 0 | |||||||
a-1. Are any constraints binding?
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Yes
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No
a-2. If so, which one(s)?
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Machine and materials
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Machine and labor
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Materials
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Labor
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None
b-1. If the profit on product 3 was changed to $22 a unit, what would the values of the decision variables be?
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The decision variables would change
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The decision variables would not change
b-2. What would the new value of the objective function be? The objective function value Z = c-1. If the profit on product 1 was changed to $22 a unit, what would the values of the decision variables be?
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The decision variables will not change
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The decision variables will change
c-2. What would the new value of the objective function be?
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There is no change in objective function value
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There is change in objective function value
d-1. If 10 hours less of labor time were available, what would the values of the decision variables be?
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The decision variables will not change
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The decision variables will change
d-2. What would the new value of the objective function be?
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The objective function value will not change
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The objective function value will change
e. If the manager decided that as many as 20 units of product 2 could be produced (instead of 16), how much additional profit would be generated?
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None
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Any change in profit
f-1. If profit per unit on each product increased by $1, would the optimal values of the decision variables change?
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Yes
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No
f-2. What would the optimal value of the objective function be? (Omit the "$" sign in your response.) The objective function value Z =
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