Glycerin at $T=20C$ flows down a channel with a pressure gradient of $\frac{dP}{dx}=1\mathrm{.}6k\frac{N}{m^3}.$ The velocity distribution is described by:

$V=\frac{1}{2}\frac{dP}{dx}(By-y^2)$

where $B=5\mathrm{.}0cm$ is the channel width. Find $V$ and $$ at $y=1\mathrm{.}2cm.$

$($Previous Chegg answer said V $=28\mathrm{.}25$ m$/$s but it is incorrect$)$