Got this question wrong because I don't know how to go about it please help. Include step by step and formulas used

3. 3. 2 kg box is placed on a horizontal surface. The coefficient of static and kinetic frictions are 0.3 and 0.2 respectively. Determine the friction force acting on the box for following cases. Clearly indicate the value of friction force. (ex: circle your answer) a) No applied force on the box acceleration of the box b) 6 N horizontal force is applied on the box. f = ma 6 = 2 0 . 3 x 2 x 918 - (5, 880) c) 12 N horizontal force is applied on the box 12 = 20 .6 x 2 x 98 = 11. 760 d) Vertically downward 8 N and 16 N horizontal force applied on the box same time. 16 = 29 84 2 x 9:8 = 15.68 +