Question: GRAVITY ON EARTH BY SIMPLE PENDULUM L (Length (m)) t for 10 cycles (s) T (s) T^2 (s^2) g (m/s^2) 0.3 m 10

GRAVITY ON EARTH BY SIMPLE PENDULUM

 

L (Length (m))t for 10 cycles (s)T (s)T^2 (s^2)g (m/s^2)
0.3 m10   
0.5 m16   
0.75 m18   
1.00 m21   

 

a. Fill in the above table.

b. Find the g average for the 4 trials.

c. Use g = 4 x (3.14) ^2 x (L/T^2) for filing in the last column.

 

t : represents the time to complete 10 oscillations or 10 cycles.

T: time for one oscillation or one cycle.

L is the length of the string.

g is the gravity constant on earth.

T = t/10

 

Use g = 4 x (3.14) ^2 x (L/T^2) for filing in the last column.

 

-please fill in the data table

-explain in detail step-by-step

-also what Formulas were used

BE THROUGH WELL DETAILED IN-DEPTH & EXPLAIN -PROVIDE AS MUCH INFORMATION AND BE CLEAR REGARDING ALL STEPS FOR UNDERSTANDING AND EXPLAIN EACH STEP BE THROUGH AND CLEAR 

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