Question: HEB 2 4 0 d = 2 4 0 m m , ( depth ) b = 2 4 0 m m , ( width

HEB 240
d=240mm,(depth)
b=240mm,(width)
tw=10mm,(web thickness)
tf=17mm,(flange thickness)
r=21mm,(root radius)
A=105.99cm2,(area)
Ix=11260cm4,(second moment of area, inertia)
ix=10.31cm,(radius of gyration)
Wcl,x=938.3cm3,(elastic section modulus)
Wpl,x=1053cm3,(plastic section modulus)
Iy=3923cm4,(second moment of area, inertia)
iy=6.08cm,(radius of gyration)
Wcl,y=326.9cm3,(elastic section modulus)
Wpl,y=498.4cm3,(plastic section modulus)
J=103.6cm4,(torsion constant)
Cw=476280cm6,(warping constant)
Could you asking my question don't use the ksi or in use cm,m and Kn
HEB 2 4 0 d = 2 4 0 m m , ( depth ) b = 2 4 0 m m

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