help complete the table

tan azimuth $($or bearing$)AB=\frac{\text{d}\text{e}\text{p}\text{a}\text{r}\text{t}\text{u}\text{r}\text{e}AB}{\text{l}\text{a}\text{t}\text{i}\text{t}\text{u}\text{d}\text{e}AB}$

Departure $=L^{**}$Sin$()$

Latitude $=L^{**}$Cos$()$

Linear misclosure dep. ${?}^2+$ lat $($:${?}^2$