Question: Help please 1] log(7x) + 4 = 5 2] 2 10g2 (x + 2) = 10 109(7x) = 1 X = 10 logz (242) 5

Help please

1] log(7x) + 4 = 5 2] 2 10g2 (x + 2) = 10 109(7x) = 1 X = 10 logz (242) 5 7x = 10910 X = 1. 429 X = 10' 3] 2 - 6Inx = 10 41 5 - log 8x = 2 - 2 - 2 =X - 6Inx = 8 - 6 - 6 X2. 2436 ex = 3 5] 4 + log,(3x - 7) = 6 6] In(1 - 3x) + 3 = 9 7] log2 2x + log2 x = 5 8] log6 (2x - 6) + log6 x = 2 109 x (2X-6 ) = 2 0:2x 2- 4x-36 3.-6 0 = x 2 - 3x - 18 62 = X (2x-6) 0= (*+3) ( x - 4 ) X = - 3 x= 6 36= 2x- 4x 1096(26- 6) 1096( 6)= 2 . 3 6 36

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