Here I have question 6 from a maths paper. I have attempted 6i but I do not understand 6ii and I dont understand the mark scheme. Could you please solve 6ii but so that I understand.

6 In the past, Angus found that his train was late on 15% of his daily journeys to work. Following a timetable change, Angus found that out of 60 randomly chosen days, his train was late on 6 days. (i) Test at the 10% significance level whether Angus' train is late less often than it was before the timetable change. [5] late : 6 10% . AM=Q. 15 Ho : P = 0- 15 H (X 2 0 15 H : P yo- 15 Mean .h( 60X6 15 60 X0.15 X0-85) n (9 , 7.65 ) So for it to be more it fre cant be 6 S must be 6.5. 6 5 - 9 17.65 - 0-904 2:904 6 1. 282 No cudence train is late less offen.Question Answer Marks Guidance 6(i) Ho: p = 0.15 Accept Ho: u = 9 Hi:p 0.1 ft their 0.904 No evidence train late less often Alft Use of Bin (60,0.15) to give Pr (