Question: Hi I need help with these questions I solved some of them and please help me with the rest let me know if there's an

5. A store sells apples for $2.99 per pound. The average mass of one apple is 84.0g. Approximately how much would it cost to buy 15 apples? 1pound=453.592gaams1apple=84.09applesin1pound=84453.592=5.45.4apples=$2.995arples 6. It takes 1200.0kg of coal to produce enough energy to make 1.00kg of aluminum metal. If a single soda can requires approximately 15.0g of Al, what mass (in kg ) of coal would be needed to produce a 24 cans? 1 Can of Al repuires 15,09 of AL 24 cans of Al requires 15/24=360g of Al 1200kg=1kg or lioo gr of AL 1000grm1200kgcosl 360g=10001200360432kg of coal 7. A case of water at a local 'warehouse store' contains 40 bottles, each with a volume of 500.0mL. How many cases of water will have a total volume of 2.001017 liters? (40500mL)500m)=0.5L20000mL20L20vitter2.001017Liters= 8. You're throwing a pizza party for 23 people and figure that each person will eat 3 slices. You call up the pizza place and learn that each pizza will cost you $14.78 and it will be cut into 12 slices. How many pizzas will you have to buy and how much will they cost? I person = 3 slices 23person=323=695lices12slice=1pi22ax3)=69slicein(1/1269)pizas=5.75ppra575pina=23ppl.7piz2a=514.78Piceof535pi22a.$14.785175=9$84.985or$84.99 9. Convert 58.00cm3 to in3. (2.54(m)3=(1in)358.00cm316.317cm31in3=3.54in3 10. Convert 0.00025cm3 to nm3. 11(mm31cm30.00025cm3=(1107)3)3=11021nm31m311021nm3=2.51017nm3 11. The density of pure copper is 8.89g/cm3. Calculate the mass, in kg, of a copper cube that is 2.00 inches on all three sides. (Volume of a cube, V=s3 ) pure copper =8.89g/cm3 V=s3(2.0)3=8Icm3=8.81g31cm3=0.061in30.061in3=8.89103kg8in3=(0.0618.891038)kg 12. Calculate the volume in in 3 of a 0.0750kg bar of silver. The density of silver is 10.5g/cm3. =10.5g/cm310.5g=1cm310.59103=0.06in3 13. Determine the number of atoms that could fit in a box with a volume of 50.0cm3. The volume of a single atom is 0.00400nm3. Volume of a base ball =50.0cm37nm3=102cm3 vidant of a single atom =0.00400nm3 so, 0.06400nm3=0.00400162cm3 No.ofatoms=VulumeofesinginatimeVolureofbarebal4=0.00450.0cm3 14. A 410.0mg piece of gold is hammered into a sheet measuring 23.0cm17.0cm. What is the thickness of the sheet in meters? Density of gold is 19.32g/cm3
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