Question: Hi I need your help in explaining why is it that I use A=r2 to calculate the area in Q = V x A? Isn't

Hi I need your help in explaining why is it that I use A=r2 to calculate the area in Q = V x A?

Isn't it supposed to be 2rL? The question is below (Do not need to explain the rest of the following steps), Thanks help a soul plz

Hi I need your help in explaining why is it that I

use A=r2 to calculate the area in Q = V x A?

Water is flowing through a steel pipe 3m long at a volumetric flow rate of 5L/s. If the pipe is 6cm in diameter what are the frictional losses associated with this fluid transport situation? Relative roughness is 0.01 . Calculate the head loss due to friction in the pipe. Example Q=VAV=AQ=(20.06)25103m3=1.77m/sRe=DV=103Pa.s1000kgm30.061.77ms1=106,620105 (Density of water =1000kg/m3, viscosity of water =103Pa.s ) From Moody chart, Re=105 and relative roughness 0.01 : friction factor f=0.0093 Pressure Loss =Pf=2f(DV2L) Head Loss =m=2f(DgV2L)

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