Hi there, based on above please answer these two questions

e) Calculate the probability that the project can be completed within 38 weeks of the expected duration, Te. Determine the certain duration that the project can be completed.

f) Construct the Gantt chart and resource allocation diagram based on the schedule. Then level the resources if the manpower available is limited to twenty (20).

Table 2 Activity Immediate Predecessors Estimate Activity Times (Weeks) Activity Activity Manpower Expected Variance Requirement Time (te) a m b A 5 6 7 7 B A 8 8 8 5 A 6 8 10 6 D A 5 6 7 8 E B 5 6 13 5 F 5 6 7 10 G D, F 3 6 9 10 H C, E 4 4 10 8 I G 2 8 14 6 J F, I, H 4 6 8 8 Solution: a: Expected times and variance: Solution: Expected time of each activity, 1, +4.tm + Activity 6 6 0.11 B 8 8 0 5 6 7 8 8 8 6 8 10 5 6 7 8 0.44 D 6 0.11 E 5 6 13 7 1.78 F 5 6 7 6 0.11 G 3 3 6 9 6 1 H 4 4 10 5 1 1 2 14 8 4 0 00 J 4 6 8 6 0.44 b: AON Network Diagram: . H c: Critical Path (b) The critical path in the network diagram has been shown. This has been done by double lines by joining all those events where E-values and L-values are equal. The critical path of the project is : 1-2-4-6-7-8-9 and critical activities are A, C, F, G,1,J The total project time is 40 The network diagram for the project, along with E-values and L-values, is 3 Ez = 14 (7) B(8) 5 L3 - 22 d(0) 1 A(6) E4 = 14E, = 21 2 C(8) 4 H(5) 24 - 14 L3 = 29 E = 0 E, - 6 D(6) F16) G(6) 7 21-01 (8) 8 J(6) 9 6 E. = 26 Es = 34 E = 40 L. = 26 d(0) Is = 34 L = 40 (0) + d(0) 26 = 20 22 = 6 E = 20 Hence, the critical path is ACFGIJ and its duration is 40. The standard deviation of the critical path will be, o= 0.11 +0.44 +0.11 +1+4 +0.44 = 6.1 = 2.470 d: Probability of completion within 36 weeks. Hence, Let us calculate the z statistic value. Hence, X-M Z= 36 -40 = -1.62 2.470 Hence, Plz