Hi this is calculus 2, multivariable calculus.

My question is on the attached photo. Can someone please explain to me the format of this question? I am a visual learner, so if you can, could you please sketch out what the question is saying? Also, can you please give me a detailed explanation, explaining each of your steps when solving the question. Thank you so much!!

Find the slope of the line tangent to the curve of intersection of the surface z = J4x? + 3y? and the indicated plane at the point (-2.4,8) on the surface :. (@) y=4 (b)x =-2 \f\fPAGE NO . : DATE : step to sketch the figure' - The surface Z= Vuz+zy 2. This represent an elliptic paraboloid, which means upwards. The surface will vise steeply along the m. asus because of 4312 team and less steeply cilong the y-axis. because of By2 term. 1 Z 3 n 10 Understand the plane intersection - J= 4 urrepresents a vertical planes parallel to the miz- plane . hence Z = Vun? + 314,2 = Vyn2+ 48 Sketch this clive on the 2 -plane with y= y. Similarly 21=-2 vrepresents a vertical plane parallel to yz- plane. 2 = V 41- 212 + 3 yz = \\/16+ 342 sketch this ewwve an yz plane with fined 7 = - 2 . OO SHOT ON REDMI 7 Teacher's Signature AI DUAL CAMERAPAGE NO.: DATE : Equation of tangent line in the drurection y= y Since m= - 1 4 8 2- 8: + ( 2+ 2 ) 2 = - 2+6 in direction as-2 . here m= 3/2 2 - 8 = 3 ( 8-4 ) 2 = 28 + 2 The tangent line to the clive at the point ( - 2 , 4, 8 ) will be line that just touches the curve at this point . Once we have equation of tangent draw it to get irequired result . OO SHOT ON REDMI 7 AI DUAL CAMERA Teacher's Signature