Question: how do we go from x(t) = A cos(t) + B sin(t) x'(t) = -A sin(t) + B cos(t) to (t) = [ cos(t), 1/

how do we go from x(t) = A cos(t) + B sin(t) x'(t) = -A sin(t) + B cos(t) to (t) = [ cos(t), 1/ sin(t) ] [ - sin(t), cos(t) ]

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