How much heat is required to convert $19\mathrm{.}3g$ of liquid benzene $(C_6{H}_6)$ at $59\mathrm{.}0C$ to gaseous benzene at $100C?$ The boiling point of benzene is $80\mathrm{.}1C$ and $C_m[C_6{H}_6(l)]=136\mathrm{.}0\frac{J}{\text{m}\text{o}\text{l}C},$ and $H_{\text{v}\text{a}\text{p}}=30\mathrm{.}72k\frac{J}{m}ol,C_m[C_6{H}_6((g))]=82\mathrm{.}4\frac{J}{\text{m}\text{o}\text{l}*C}.$

Express your answer with the appropriate units.

$q=$